added weekly exercises of isp-ws25

c/isp-ws25/weeklies/week10/w10ex01.c

@@ -0,0 +1,65 @@
+/*
+In this task, you should find mistakes in the given source code.
+The idea is to represent multiple characters as words stored as linked lists.
+The code creates five elements of the struct Character.
+
+Each element has a member content_ (the actual character) and
+a pointer to the next character in the word (next_).
+
+The printAll-function should correctly print all the elements inside the linked list.
+
+Unfortunately, there are some errors in the code.
+The compiler finds a few of them, others are logical errors and are not detected by the compiler.
+
+Zum Beispiel:
+Resultat
+hello
+*/
+
+//#include "stdio.h"
+#include <stdio.h>           // General libraries should always be included with <>
+                             // including with "" searches in compile directory first
+
+typedef struct _Character_
+{
+  char content_;
+  //Character* next_;
+  struct _Character_ *next_;
+} Character;
+
+void printAll(Character* head)
+{
+  //if (head = NULL)
+  if (head == NULL)
+    return;
+
+  Character* it = head;
+  while (it != NULL)
+  {
+    printf("%c", it->content_);
+    it = it->next_;
+  }
+}
+
+/*
+If you want a recursive printAll call:
+
+void printAll(Character *head)
+{
+    if (head == NULL) return;     // guard against empty list
+    putchar(head->content_);      // if here, prints first -> last
+    printAll(head->next_);
+    putchar(head->content_);      // if here, prints last -> first
+}
+*/
+
+int main(void)
+{
+  Character e = {'o', NULL};
+  Character d = {'l', &e};
+  Character c = {'l', &d};
+  Character b = {'e', &c};
+  Character a = {'h', &b};
+
+  printAll(&a);
+}